topic Re: Remove unused characters from string in LabVIEW

Remove unused characters from string

concorpoly — Mon, 13 Feb 2012 21:41:10 GMT

Hi, I try to remove unused characters from a string, but I can't find a function to do that.

The string like: 0000 0000 0000 0000 0000 0000 0130 3130 3030 3030 3004 0000 0000 0000 0000 0000 0000 0000 , I need the characters from 01 to 04.

I need some tips.

Re: Remove unused characters from string

altenbach — Fri, 20 Mar 2026 14:29:39 GMT

String subset?

(Is your example string displayed in hex?)

Re: Remove unused characters from string

johnsold — Mon, 13 Feb 2012 21:45:18 GMT

First, what defines an "unused character"? Are all the unused characters 00? Can 00 ever occur in the desired data? Are the characters 01 and 04 always the first and last characters? Can either of those characters occur in the data?

Removing characters is not difficult. There are several string and array functions which may be used. To decide which to use and how to use it, the decision making porcess muct be defined first.

Lynn

Re: Remove unused characters from string

concorpoly — Mon, 13 Feb 2012 21:46:24 GMT

yes, 0x00 and \00, NULL character. the string I posted is in Hex mode.

Re: Remove unused characters from string

concorpoly — Mon, 13 Feb 2012 22:14:56 GMT

yes,unused characters are 0x00 and \00, NULL character the string I posted is in Hex mode.

Re: Remove unused characters from string

jcarmody — Tue, 14 Feb 2012 11:18:27 GMT

You could use Search and Replace String to remove the null characters. It doesn't help if you have valid nulls within your data, but it's a start.

Re: Remove unused characters from string

PhillipBrooks — Fri, 20 Mar 2026 14:30:00 GMT

If the characters between the SOH and EOT did have an NULL, then Match Regular Expression might be a choice:

Find \x01, find anything BUT \x04, then find \x04