How can I get an actor has how many messages and what names they are？

[yanzhanglin]

for example .this actor has 2 messages， named Method1 Msg.lvcalss and Method2 Msg.lvcalss，Is there a way to obtain them？

[p4keal]

You can use the property node App.AllLibslnAppInstance. I have attached an example of how to find child classes starting from a given parent class. You can easily adapt this to find message classes in a virtual message folder. You can even make your life easier by defining an intermediate class for each actor that inherits from Message.lvclass and changing the inheritance of your actor's messages. In this case, you can use the snippet without changes.

Message.lvclass <- 1. Class Msgs| <-  Msg1

                                                      | <-  Msg2 

[yanzhanglin]

if I build exe,this methods seems to doesn't  work..

[p4keal]

Just put an object of all used classes in one vi, actor core for example. Than it should work.

[CaseyM]

I'm not sure how you mean this to work in an EXE, but during this development, this utility is meant to do exactly what you're describing:

https://www.zyahsolutions.com/blog/bowzer-the-browser

https://www.vipm.io/package/zyah_solutions_lib_bowzer_the_browser/

[CaseyM]

I should also note that because the utility recognizes and leverages interfaces, it works with projects built in LabVIEW 2020 and later.

[yanzhanglin]

it seem to use Pre-Build Action VI can achieve my goal，I just want to konw what an actor can do，then I dynamic call message

[CaseyM]

You want to dynamically determine an actor's API and then use that information to send those messages? What's a use case for this (I'm genuinely curious)? How do you plan on populating message classes that have inputs?

[yanzhanglin]

I use string as every message‘s private data，these private data read from config files 

[drjdpowell]

Are you sure you should be using the Actor Framework?  Different frameworks make different design choices, and you seem to want to use complicated techniques to undo the choices the AF makes.