Hello, everyone I want to use the UDP protocol to send a message from computer #1 to computer #2 with this format First byte: Message ID Second byte: number of message bytes n Third byte: the message How I can send that message by that format , could anyone help me?. I try to do that by this way, is that way is a right way?.... In the message to be send (string indicator box) dose 1 represent message ID (M Id), - sign represent # of bytes and is the first byte of message is the index 0 of array , second byte is index 1 , third byte is index 2 ,......etc Best regard Zhrani

Cool, that is what I thought your were trying to do. You need to use logical shifts form the command. You will shift the first byte over 8 bits, the second byte over 4 bits and the payload over none. Then you can add them all into a single number and send this number over a single udp command. This give you a total message length of 3x4 = 12 bits. To illustrate, lets pretend that we have the following scenario: Message ID: 255 (1111 in binary) Number of bytes: 0000 (0000 in binary) Message: 255 (1111 in binary) The below program shifts arranges them into one 12 bit message using shifts: You can then send this number over udp. Is this what you were trying to do? Could you tell me more about where you got this requirement? Was it from the manuals for the micro controller or a different source? I still don't understand why you need to send these commands in this fashion, which will help me answer your question much more effectively.

Industrial Communications

how you can send 3,4 byte under UDP protocol

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Thankyou too much Jesse_D

that's what i want

Best Regard

Alzhrani

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Industrial Communications

how you can send 3,4 byte under UDP protocol

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