12 bit Decimal to binary converter with 8 bit msb and 4 bit lsb

[DKLabView]

I want to make a vi  12 bit decimal to binary converter  with 8 bit MSB and 4 bit LSB

Thanks in advance

[Norbert_B]

There are no 12 bit numbers in modern CPUs. Numbers are 8, 16, 32, 64 or 80 bit usually.

That being said, your number is already a subset of another number (most likely 16 bit).

Using the "Split Number" function in the Data Manipulation palette, you can split it to two 8bit numbers.

It is not possible to split a number to 4 bit.

Norbert

[GerdW]

Hi DK,

some elementary math may help:

[Norbert_B]

Hehe, good example, Gerd.

Working with "masking" (the AND-operation) will reduce the amount of significant bits to a desired amount. Still, the number itself is of higher resolution.

So when using this approach (which is the only possible), you have to keep in mind that computing values with that "12bit" number might require some additional masking functions (e.g. addition, multiplication, ..)

Norbert

[DKLabView]

Will You Please upload The Vi

[GerdW]

Hi DK,

this "VI" consists of just 2 basic functions and 2 constants, you should be able to recreate it in a minute.

And it's a snippet anyway...

[DKLabView]

Hi GerdW

 sorry i dont have much experience in labview. I didnt able to fix the constants

[GerdW]

Hi DK,

you get experience by programming on your own 🙂

Create a numeric constant, set it to U16, show the radix, input the values as shown above...

[DKLabView]

Thanks I am trying ..but i didnt able  to enter the value

[GerdW]

Hi Dk,

it seems you didn't follow that simple 4 step procedure:

- create a numeric constant

- set the representation to U16

- show the radix (and set to hex as shown above)

- input the values I used above...

Come on...