LabVIEW
2’complement hex convert
Solved!
Aojha wrote:Although I would like the person posting the question to arrive the solution by himself through disscussions.
The problem was that your discussions were leading the the person into a deep swamp, making the solution appear much harder than it actually is. 😮
You shoud really start a new thread with this unrelated question. This thread is already marked as solved!
Aojha wrote:I also tried with .dat file and read from binary file but got same error
You are not providing any information. ".dat" is just a generic file extension, and gives a absolutely no useful information on how the file is structured. Where does the file come from? Who wrote the file? How was the file initially written?
If you want help, attach an actual data file as well as the VI that gives you the error. But first start a new discussion thread!
In fact, your last posts are all pure gibberish and make absolutely no sense:
@Aojha wrote:
Let me make myself clear,
any signed bit is +ve if msb is 0 and -ve if msb is 1. I did not type casting and flattening dunction at that time. But I knew How to use msb information to get a solution. So i suggested to use string functions to swap bytes.
You are not making yourself clear. I am not familiar with the abbreviations -ve and +ve. The problem was not msb, but 2's complement. Appanrently you were unaware that the binary reprensentation is 2s complement already.
@Aojha wrote:
Hi @altenbach,
In your vi I tried to modify the values in Array of strings. But could not do so.
If I creat additional control then I can modify it. How could I achieve this so that no one can modify the inputs?
You are not explaining what you tried to modify. What kind of "additional control"? Modify what (what is "it")? Achieve what (what is "this"?). Do you have problems creating a diagram constant?
@Aojha wrote:
hi, I tried to read a file and Unflatten it to a Waveform but got this error. I am getting same error even if I am reading a .dat file through read binary file.
Your attempt shows that you have absolutely no idea what unflatten actually does. did you even read the help? You can only unflatten to a waveform if the file actually contains a flattened waveform. Your file is formatted text, nothing flat or binary at all.
Unflatten from string is not some magical block that can read your mind and digest whatever you throw at it. It is the opposite: You need to know exactly how the string is structured.
How did you try to modify the value?
What happened instead?
Modify to what new value?
Since the string is in hex display, it will only accept numbers 0..9 and letters A..F, so don't try to enter random text.
You really need to formulate your posts with more useful information. There are millions of possible ways something does not work and if you don't tell us the details, we cannot help.
