Case structure with range of string characters ("A".."Z") doesn't include last character in the range

[scofield]

Is this a bug?

Intention: filter the string character based on whether or not its an 'alphabet' character.

Approach 1 (Loop 1): Using case structure with string characters as range ("A".."Z", "a".."z")

Issue: last characters in the specified range ("A".."Z", "a".."z"), which is "Z" and "z" are not included.

Solution 1 (Loop 2): Include next character in series so that required character is no longer the last character. Instead of "A".."Z" make is "A".."[" and instead of "a".."z" make it "a".."{"

Solution 2 (Loop 3): Include the last character ("Z" or "z") again.

The default case (in all case structures) contains a FALSE constant.

Lower two loops give me intended result (filter all characters other than alphabets).

[BertMcMahan · Accepted solution]

No, that's the correct behavior for strings. The Help file for case structures links to this:

https://zone.ni.com/reference/en-XX/help/371361R-01/lvhowto/case_selector_values/

Numeric ranges are inclusive, but string ranges are not.

Try using Match Pattern instead:

[altenbach · Accepted solution]

A good tool here is lexical class. (Make a case for 4&5)

Some examples:

[Darren]

We discuss the issue of string case structure ranges in my nugget post on string case structures.