LabVIEW
Comparing two 1D array strings
Solved!
Please define what you mean by "difference". Do both arrays have the same length? Does order matter (e.g. do you want all elements that only occur in one of the arrays). Do you only want to compare elements with the same index? etc.
Easiest would be to attach a simple example containing typical arrays (with default data) and the expected result.
Thanks for the files. Using "Sets" would have been my first suggestion too, but that requires at least LabVIEW 2019 and you did not mention what you have. Even without sets, the solution would have been significantly simpler than your code. 😉
What creates these files? Are files only added to the folder or is it also possible that some disappear after a while? You might also look for a case insensitive solution. Does the process repeat? (e.g. do you want to check for new files repeatedly?) Are the file names simple numerics and arrive in sequential numerical order? What should happen with the found difference later? Also note that if you would create these files with sufficient leading zeroes (0004.csv instead or 4.csv), an alphabetic sort would be equal to a numeric sort. (11.csv comes before 2.csv but 0002.csv comes before 0011.csv).
@Abraham11 wrote:
Are the file names simple numerics and arrive in sequential numerical order?
Yes the files will be of seqence of numbers.
All you need is keep a single integer in a shift register (initialized with 0 or 1, depending on how the files start out), indicating the "newest file+1" from the previous read, then, after the elapsed time, test and increment it until a corresponding file does not exist in the list.
