02-20-2008 12:47 AM
02-20-2008 01:28 AM
02-20-2008 01:34 AM
Hi Kousy,
In your attached jpg, you set the input "a" as -Inf. And in your formula, you calculate (x-a)*(d-c)/(b-a). So you get the output as NaN.
You might need to check the value for parameter a.
mchen
02-20-2008 04:58 AM
Hi,
My attached vi clarifies my problem.
Inf is creating a confusion i know, may be I need to do some work around.
Kousy
02-20-2008 09:14 AM
02-23-2008 12:26 AM
02-25-2008 05:08 AM
02-25-2008 05:23 AM