Fundamental test question

[ajmartin]

How does this even work? (see atachment) How do you know what the feed back loop is initialized to? I built this VI and put probes on it. The output of the FB is always zero. This is what I can tell , the index is saying to start insert at the second element in the array. The I terminal is element to insert (0,1,2) for the 3 itterations.  The out put of the FB is the array to insert into.

What am I missing?

Alan

[Cory_K · Accepted solution]

The answer is going to be D.

The array is initialized to

[1 8 6 2]

This is done by passing the array to the blue dot on the left side of the for loop.

Iteration 0

[1 0 8 6 2]

Iteration 1

[1 1 0 8 6 2]

Iteration 2

[1 2 1 0 8 6 2]

So you are left with choice D

Message Edited by Cory K on 09-15-2009 11:18 AM

[ajmartin]

Well thanks for that. I have studied arrays and For loops, but was a little iffy on the feedback things, so I used LabVIEW detailed help. I knew the problem was in initializing the FB but I could not see any way to do it in this case. I mistakenly thought the blue dot was a tunnel. It went down hill from there. I see it now and now my example VI works

Thanks!

Alan

[Harold_Timmis]

please mark cory k as the solution

[ajmartin]

Sorry , Im new around here. I think I gave the Kudos correctly, How do I mark cory K as the solution?

Alan

[Harold_Timmis]

go to option at the top right coner where you have marked your solution and select unmark as solution and than mark cory's