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How do I find the reference's terminal

Hello,

Will you please tell me how to find the terminal to the reference or explain why this is possible?

I have inherited this large program and the originating author is not available.

The attached screen shot shows the grayed out find >> terminal.

Thanks,

MoWW

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Message 1 of 12
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I don't know why it's grayed, but can you find the control and then double click it to get to the terminal?

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Message 2 of 12
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Hello,
 
The control is hidden, i.e., when I Rt. Click >> Find >> Control the control is shown on the Block Diagram but when I click the control it is not visiable.  Therefore, your suggest is not possible.  I do however thank you for the suggestion.
 
Thanks,
             MoWW
 
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Message 3 of 12
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Wire the reference into a property node and select the Visible property. Set it to T and run the program. The control should be visible now.

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Message 4 of 12
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Hello,
 
The suggestion did not work.  Maybe I did not do as intended.
The attached screen shots of before running and after running the VI.
 
I don't know how this was done so if more suggestionsor an explination of how this was done, I will be glad to hear it.
 
Thanks for the help.
 
MoWW
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Message 5 of 12
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I am new to labview as well, but i believe that you have to right click on the property node and select "Change all values to write".  The arrow and wire will also go into the left side instead of the right.  Then set the value with a T/F constant.
Message 6 of 12
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lapres_3 is correct, but what I find weird is that your LED is T, meaning that LV does think that this cluster is visible.

It looks like this code is inside an event structure. Did that section of code actually run, or did the value stay true from before the program ran?
Other than changing it to Write, make sure that this code is also executed.


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Message 7 of 12
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There are only two things I can think of that would cause the "Terminal" option on the Find pull-right menu to be grayed out.  If the control is a Subpanel, it won't have a terminal...but that's not your case, since you have a Cluster.  In your case, your cluster must reside inside an array or another cluster...this would result in it not having a terminal on the diagram.

It also makes sense to me that the Visible property would be set to True...I think what's happening here is that there is an invisible cluster on the panel, and your cluster is inside of it.  The "Visible" property does not propogate...meaning, if an owning control is set to invisible, its contained controls will still return a Visible property value equal to whatever it was originally.  So you need to find the owning cluster and make it visible so that you can see your cluster.

I hope all that made sense.  Let me know if you're still having trouble.

-D

Message 8 of 12
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That does make the most sense, although it doesn't seem to match what's shown in the picture (unless the other cluster is either very large or invisible).

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Message 9 of 12
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If my theory is correct, the other cluster is *both* large and invisible.  🙂  And if my theory is incorrect, I want to see a sample VI that demonstrates the problem attached to the next post... 😉

We'll see what happens...

-D

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