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How to determine the end of sentence

I have some text for example:

"I love a girl. Her name is Sue. She lives in PA."

Now I want to write a program to separate it into 3 strings and put them into array, so I use a while loop and "Match Pattern" vi. My plan was to find  "." . However, it doesn't work becuase ".". in Labview mean any character. Does anyone have any clue what I should do?

thanks

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=Labview 7.0 & 8.0 & 8.5=
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Message 1 of 4
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Exact same answer as give in this answer give earlier today.
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"\."

Preceed the point by a  backslash.

The point is a special  character, see help for the match pattern function -> special characters.
Regards,
André (CLA, CLED)
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Message 3 of 4
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How are you going to handle:

"Mr. Jones lives across the St. Paul River from Sue."

Lynn
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