If statement depending on 3 LED status

[biff222]

Hello,

I am trying to execute an IF statement depending on 3 the status of 3 boolean values.

I have 3 array's of 10 numbers each being compared against a range of values. If the value falls within the range an boolean indicator is lit.

What i want to be able to programme is that if the 1st boolean indicator is lit for all 3 arrays then a true case structure will run. If they are not all lit then the false case will run.

I want this to happen for the 1st number in all 3 arrys, then the 2nd, 3rd etc till all 10 numbers of all 3 arrays have been compared.

Hope that makes sense and someone can help me?

I basically want IF boolean indicator is lit AND boolean indicator lit AND boolean indicator lit THEN......ELSE......

[sebster]

Is this what you're after?

[ChrissyC]

Hi,

You can use the boolean logic operators to do this - the AND operator specifically. The "compound arithmetic" function would be the best bet here - allowing you to wire all three LED status's into one VI.

Then simply wire the output of the Vi to your case statement.

-CC 

[edit: Grrr, beat me to it Sebster! ] 

[JÞB]

Inrange and coerce can accept arrays of ranges and values and will output an array of booleans. bool array to number and use the number to drive your case select.

[Yogesh_Redemptor]

Check This Logic; You can replace the build array with replace array.

Regard,

Yogesh Redemptor

[altenbach]

I would probably do something as follows:

 

[JÞB]

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@altenbach wrote:

I would probably do something as follows:

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Only if your sure the logic never changes.  bool array to number allows any condition to be added to the case

[altenbach]

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@JÞB wrote:
Only if your sure the logic never changes.

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I was pretty sure after reading this:

"... is lit for all 3 arrays then a true case structure will run. If they are not all lit then the false case will run."

😄