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LabVIEW Embedded ARM build error

I'm getting this build error now on a VI that is a simple UDP write in a while loop using a string constant for the source.

 

[11:53:35 AM] Status: Error

linking...

.\Obj\LabVIEW.axf: Error: L6218E: Undefined symbol CopyErrorInToOut (referred from rlarm_ccgtcpudpsupport.o).

.\Obj\LabVIEW.axf: Error: L6218E: Undefined symbol SendError (referred from rlarm_ccgtcpudpsupport.o).

Target not created

 

Status: Build failed.

 

This worked previously.

 

Chris Megdanoff

Picometrix, LLC 

 

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Hi Chris,

 

Did you make any changes at all to the code, to the front panel, or to the LabVIEW project before this error started? What version of LabVIEW are you using?

 

I've seen a couple issues that result in similar error messages. Have you created any interrupts and left them unconfigured? Are you using modern controls or classic controls? Are you doing any type-casting?

 

If your VI is simple, posting a screenshot of the block diagram would be helpful.

Product Support Engineer
National Instruments
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