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Numerical Inputs reset to 0 when while loop stops. Snippet attatched

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vi snip.png 

Could some one please tell me how I make my numerical inputs down the left hand side reset to 0 when the while loop gets its stop signal?

Much Much appreciated

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Solution
Accepted by topic author metsystemalex
Here's an easy way to do it.

reset.png

PS - If I had LV2009 I'd download that snippet and make it a lot simpler, or die trying. 🙂
Jim
You're entirely bonkers. But I'll tell you a secret. All the best people are. ~ Alice
For he does not know what will happen; So who can tell him when it will occur? Eccl. 8:7

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Simple counting reveiles, that you could use an 4x6 array. You can simplify the comparisons by using the polymorphism of the Equal primitive (yes, they work for arrays: right click to select if you want a boolean array out for each element or a single boolean if all elements are equal).

 

And very important: The equals might fail! Use I32 as inputs. The doubles might not be equal in the last digits because of numerical errors, hence you might evaluate 3=3->false (one is 2.9999876 and the other 3.00000123).

 

Felix

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PLEASE STICK TO ONE THREAD. This is the third thread you've created on this same subject. Original thread.
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First of all apologies for posting multiple threads. I feel like i have broken a cardinal rule of the forum.

 

Secondly could you please tell me what and where i can find those instructions inside your flat sequence snippet.

 

cheers

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Everything is on the Application Control palette.

 

When you drop the  Invoke Node onto the diagram, right click on it anddo 'Select Class>VI Server>VI>VI'> Then right click againon it and select 'Methods>Default Values>Reinitialize All to Default'.

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metsystemalex wrote:

 

Secondly could you please tell me what and where i can find those instructions inside your flat sequence snippet.

I did not have a flat sequence snippet. That's an event structure, and I explicitly told you in the response how to create the invoke nodes.

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