Overlaid Cursor's Movement

[NitzZ]

Hi all,

Scenario

I have a graph with 2 cursors say Cur_1 and Cur_2. Cur_1 can have any Y value and Cur_2 has a Y value that is "Num" less than the Cur_1 Y value where "Num" can be any number.

Example, If Cur_1 = 50 and Num = 10, Then Cur_2 = 40

When ever Cur_1 is moved, Cur_2 is programmatically moved accordingly. Cur_2 can be moved independently but its Y value cannot be greater than Cur_1 Y value.

Problem

Now the problem is when the value of "Num" is "0" then both Cur_1 and Cur_2 are overlaid. In such cases, i am not being able to move the lower cursor unless I move the upper cursor. And in my code as I expained above, Cur_2 has to move relative to the Cur_1 when ever Cur_1 is moved. So Even if i think of moving the upper cursor (Cur_1) and then move the lower one, it is not possible as the lower cursor has to automatically move according to the Cur_1 movement.

I would be glad if anyone can help me with any kind of suggestions.

Thanks and Regards,
Nitz

(P.S. -  Sorry for such a long description. I don't have a code to share with you all. So I had to expain it this way.)  

[falkpl]

Didnt totally follow but you should look at cursor events (move, grab....) and cursors can be then manipulated via property nodes.

[Florian.Ludwig]

Hi

How about a numeric control to enter Y. That way you could move the 2nd cursor from underneath the 1st one.

Regards

Florian

[NitzZ]

Hi Florian, 

Numeric control is something which would prefer if there's no other solution. I wanted to grab the lower cursor somehow when both the cursors are overlaid. 

Hi Falkpl,

I tried all the events and properties, couldn't find a proper way of doing it. 😞

Any help?

Thanks and Regards,
Nitz 

[P@Anand]

Why don't you have a check box to make the cursor 1 and 2 Visible so that you can access only the cursor you want?

[NitzZ · Accepted solution]

Hi Anand,

Making the cursor visible or invisible wont disable it.. It will still be enabled causing the below cursor not to move. I didn't get a specific solution. So I had to go ahead with a work around. I have attached it here.. You may have a look if you wish.. 🙂

Regards,
Nitz