Read on parallel port with labview 7.1

[alexis.collin@siemsn.com]

Hello

I want to read on the parrallel port an 16 bits words, i am already using the SubVI "inports 16".
I got a problem and i don't know how to use this SubVI correctly. Can you help me please?

Regards

Alex

[Ray.R]

Hi Alexis,

You can find some useful examples by using the "Example Finder" within the Help menu. Simply do a search on "Parallel Port". These should get you going. Also look at the following links:

Read the pdf in this link.

Here is another link.

R.

[alexis.collin@siemsn.com]

Hi

I write my bytes words on a parallel port and it works fine. Then i want to read them, for the 8 bits word it's ok but for the 16 bits i can't find the right address of the pin and i try on all of them with basic Labview VI "inport".
I send you the example of my send and read programm for an 8 bits word, can you help me to transform it to send and READ a 16 bits words.

(try with pilot 8 bits)

Thank you

[Ray.R]

If I understand correctly, you want to read 16 bits in a single pass using the parallel port.

That may be a challenge since there are only 8 data bits and 4 control bits (that is if my memory is correct..)

You can use the 4 control bits for data if you set the port properly (my brain does not recall all the process for this one)...

However, you'll be missing 4 bits for the word write / read. The alternative is two shots.

You could use a 16-bit latch and use a control signal to capture / release the data. However, you would need two cycle each (write or read).

It's been a while since I read that pdf doc. I do remember that there were trick you could do with the port, but I cannot remember extending it to 16 bits.

R.

[alexis.collin@siemsn.com]

Hi,

If i well understand i will be obliged to read two 8 bits words? In my last rply i've post my VI for send and read 8 bits. On it (it's not a great VI I know) i read one bit at the time at each bit send. But when i do the same thing for 16 bits word, doesn't work AND i read one bit at the time so it will be correct but it isn't.

HELP!

Thank you

Alexis

[daviddelebecque]

Bonjour,

Je crains que la solution ne soit de diviser votre mot de 16 bits en 2 mots de 8 bits.
Cordialement,

David D.

[Ray.R]

To translate what David said: "Je crains que la solution ne soit de diviser votre mot de 16 bits en 2 mots de 8 bits."


It looks like you will have to divide your 16 bits into two (2) 8-bits.

I have to agree with David.

-JLV-