Receiving GPRS Data With Labview

[dilloway]

Hello All,

I have yet to find any explicit information which details how to receive GPRS data in LabVIEW. Allow me to provide a detailed scenario. I have designed an embedded client which communicates to a Telit GM862 module using a UART. The Telit GM862 is capable of establishing a GPRS connection and using TCP or UDP to packet and send data. The Telit GM862 manual provides an example for controlling the device over tha UART:

Send: AT#SD = <conn id>, <protocal>, <remote port>, <IP address>
Receive: CONNECT
(all data sent to the UART will be packet and sent to the internet host...)

I want a LabVIEW VI to be my host which can receive this data and graph it on a plot. The problem is I know very little of LabVIEW and TCP/IP connections. My first qustion is can somebody tell me of the basic components that I will need in LabVIEW to accomplish this? Also, my host computer is on a router; how do I determine the correct IP so I can connect to it from the embedded client?

I appreciate all the help I can receive.

[Sorooshster]

Hi Dilloway,

It sounds like the basic issue is that you need to do TCP/IP communication with LabVIEW.  If you can accomplish that then you will be able to get your GPRS data and graph it.  There are a number of good examples in the LabVIEW example finder on using TCP/IP communication.  If you launch LabVIEW and from the help menu select "Find Examples" it will open the LabVIEW example finder.  Use the search tab to search for TCP/IP and you will see a number of programs that you can use as a starting point.  The TCP/IP VI's use port format for communication, so to address your question regarding the host computers IP, you well need to communicate with the port on the router and set up the router to do port forwarding.  Let me also suggest a useful resource if your new to LabVIEW.  We have a wonderful set of tutorials covering many of the basic LabVIEW topics here.  They are free and will help you get started with LabVIEW.  Thanks and have a great day.