Shift register initial value

[jyang72211]

I wrote a simple program with a while loop that contains a shift register that save the previous iteration value.  When I stop the program and restart the program again, I thougth the shift register's value will get reset to 0 (for a I32 data type)?  Apparenetly, the shift register retains the value from the previous run before I stop the program.  Why is that?  Why won't the shift register reset?

[smercurio_fc]

Because that's by design. It's also documented in the LabVIEW Help. Did you look in there?

An Uninitialized shift register is actually quite useful in creating a LabVIEW 2-style global variable, AKA functional global, AKA Action Engines.

[Darin.K]

If you would like to reset the SR without moving a wire or other trivial change, just force a recompile by pressing ctrl while hitting the run button.

[ABCPrograms]

Just wire a constant with a value 0 to the SR before entering the while loop.  Problem solved 😉

[pincpanter]

See the picture (not a snippet)

[jyang72211]

Darin,

That's exactly what I am looking for.  Can you point me the reference that talks about ctrl+run and recompiling?

[Darin.K]

This and many other fine keyboard shortcuts is available here:

http://www.ni.com/pdf/manuals/373353d.pdf

[smercurio_fc]

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@jyang72211 wrote:

Darin,

That's exactly what I am looking for.  Can you point me the reference that talks about ctrl+run and recompiling?

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Of course, that won't solve the issue when you're running the VI normally. Unless you explicitly want the shift register to be uninitialized?

[Ben]

That mask will not prevent us from finding the person who offered that extra length of rope.

Ben

Jyang,

Please see the link in my signature about "Race Conditions" to learn more about SR and how to exploit them.

[Darin.K]

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Ben wrote: 

That mask will not prevent us from finding the person who offered that extra length of rope.

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Telling someone there IS a bucket of Truth is not the same a pushing (or nudging) them in.