@CHAssoc wrote:
The reason for asking the question is that my answers for the coefficients differ from those calculated by the supplier using the same data, and I would have expected ALL mse techniques to give the same output.
Well, do you know how the supplier solves for his solution??? 🙂
If you fit 1/T = A + B*ln(R) + C*ln(R)^3 using General LS fit, you'll probably get a slightly different result compare do solving for the direct values with: T(R) = 1/(A + B*ln(R) + C*ln(R)^3) using e.g. Levenberg Marquardt, because your inversion causes a skewing of the weights of each data point depending on B or T. You are doing a nonlinear transformation! The results will only be identical if the data has no noise at all!
How different are the results?
Do you have an example data set and the result of the supplier?