deleting elements of one array by comparing it to the elements of another array

[Prakruthi]

I m a newbie to LabVIEW and I have a very basic question.

I have two arrays. The first array contains a certain set of elements

For e.g.  1 2 3 4 5 6

The second array has another set of elements

For eg. 2 5 6

Now I want to delete the elements 2 5 6 from the first array and plot the first array with the deleted elements on a waveform graph.

Can anybody help me out?

Thanks and regards.

[daveTW]

Hello,
you could do something like this:



Greets, Dave

Message Edited by daveTW on 02-23-2007 05:07 PM

[Norbert_B]

Prakruthi,

attached you can find a picture of a working solution, but it is definetly NOT the best one.

Disadvantages:
- Direct comparison with "=" should only be done with integers. Floating point number have some major issues here since 2.00 != 2.00 (not always, but more often than suspected!).
- Due to the two nested loops there could be some overhead which can be prevented with other approaches...

nevertheless, i hope this helps 🙂

Norbert B.

[Norbert_B]

Dave,

your solution looks nicer than mine, i have to admit. BUT: what if you have e.g. "5" in your array twice or more times??

Norbert

[daveTW]

Hi Norbert, you are right, this is not worth a star 
But I put in another while loop and it should work...



Greets, Dave

Message Edited by daveTW on 02-23-2007 05:26 PM

[Prakruthi]

Hi Dave,

Thank you for the quick reply. That is exactly what I tried to do. But Im doing something else wrong. My final waveform, still appears with the undeleted elements.

I have attached the vi for a better understanding.

Thanks and regards,

Prakruthi