Ok, you have me, sort of. Resitance + Capacitance /= Impedance. Resistance + (Capacitive in this instance) Reactance = Impedance When the impedance of the probe is listed it is at a specific frequency, so it actually will change. The resistance portion won't, but the capacitive reactance part will as the frequency increases. In the case of digital signals, particularly data rate ones, the frequency components of the "square wave" (fast rising digital signal) can be very high frequency, meaning that the probe can have a significant effect.
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