12-01-2009 12:47 PM - edited 12-01-2009 12:49 PM
I want to draw a mesh on a 3d graph.
As seen in attachment, the mesh can be presented on graph using 3D surface control.
But, I don't know why the z value is presented differently according to the x vector.
X_Sine mesh on Sine wave vs. X_Linear mesh on Sine wave.
Is this right?
I want to present sine mesh on sine 3D surface.
Is there a suitable way for this?
(I want to give the concept of 2d interpolation according to mesh representation.)
labmaster.
12-01-2009 01:09 PM
The linearization could be understood under sine vector in X.
I want to modify my question... How to represent the sine mesh on sine waveform with a labview control?
labmaster.
12-01-2009 01:19 PM
Your posted code shows a mesh over both plots.
I do not understand what it is you don't like or want to change.
Lacking that info I can't think of anything else to say.
Ben
12-01-2009 01:41 PM
Thanks.
How to add the sine mesh (left hand drawing) on the sine waveform (right hand drawing)?
labmaster.
12-01-2009 02:28 PM
OK thanks you!
in this thread I posted a worse case 3d graph example that uses multiple plots in the same graph using
the "add" method for each plot. Please review that thread because I explained everything that I did and I posted full code so you "can roll your own".
Have fun!
Ben