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drawing a mesh on a 3D graph

I want to draw a mesh on a 3d graph.

As seen in attachment, the mesh can be presented on graph using 3D surface control.

But, I don't know why the z value is presented differently according to the x vector.

X_Sine mesh on Sine wave vs. X_Linear mesh on Sine wave. 

Is this right?

 

I want to present sine mesh on sine 3D surface.

Is there a suitable way for this?

 

(I want to give the concept of 2d interpolation according to mesh representation.)

 

labmaster.

Message Edited by labmaster on 12-01-2009 12:49 PM
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The linearization could be understood under sine vector in X.

I want to modify my question... How to represent the sine mesh on sine waveform with a labview control?

labmaster.

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Your posted code shows a mesh over both plots.

 

I do not understand what it is you don't like or want to change.

 

Lacking that info I can't think of anything else to say.

 

Ben

Retired Senior Automation Systems Architect with Data Science Automation LabVIEW Champion Knight of NI and Prepper LinkedIn Profile YouTube Channel
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Thanks. 

How to add the sine mesh (left hand drawing) on the sine waveform (right hand drawing)?

 

labmaster.

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OK thanks you!

 

in this thread I posted a worse case 3d graph example that uses multiple plots in the same graph using

 

 

 

the "add" method for each plot. Please review that thread because I explained everything that I did and I posted full code so you "can roll your own".

 

Have fun!

 

Ben

 

 

Retired Senior Automation Systems Architect with Data Science Automation LabVIEW Champion Knight of NI and Prepper LinkedIn Profile YouTube Channel
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