floating point to fixed point conversion :::what is the algorithem

[mangood]

hi member

i have number which is a floating ponit and i converted it to fixed ponit representation by use lab view to fixed block vi

i am asking what is the algorithem that have been used by the to fixed block vi??

best rgeads

[ASEAN]

Hi Mangood,

May I know what the fixed block vi you are referring to?

Are you referring to this function: To fixed point?

http://zone.ni.com/reference/en-XX/help/371361J-01/glang/to_fixed_point/

Regards,

KwokHow

[mangood]

yes
i asking what is the algorithem that can be used to convert floating point to   fixed point with out use this VI!!!!

[nathand]

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@mangood wrote:
i asking what is the algorithem that can be used to convert floating point to   fixed point with out use this VI!!!!

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The details of the algorithm depend on the configuration of the "To Fixed Point" function (in Properties). With default values, this algorithm produces identical results. A fixed-point value is a lot like an integer, except that the first bit has a value of 2^(-n) instead of a value of 1. To convert a floating point to a nearly-equivalent fixed-point, you multiply the floating point by 2^n, then convert that to an integer.

[tst]

There's a good paper here which explains the structure of a fixed-point value - http://zone.ni.com/devzone/cda/pub/p/id/303

To clarify Nathan's response, basically, a FXP has N bits which are a regular binary integer and M bits for the fraction, which work just like the integer (you multiply and add), but the Mth bit from the point is worth 2^(-M), so .001 is (0*1/2)+(0*1/4)+(1*1/8) or 0.125.

[mangood]

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@tst wrote:

There's a good paper here which explains the structure of a fixed-point value - http://zone.ni.com/devzone/cda/pub/p/id/303

To clarify Nathan's response, basically, a FXP has N bits which are a regular binary integer and M bits for the fraction, which work just like the integer (you multiply and add), but the Mth bit from the point is worth 2^(-M), so .001 is (0*1/2)+(0*1/4)+(1*1/8) or 0.125.

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thank you