LabVIEW
if time = 3 seconds, how do i set the values of the time steps 0,0.1,0.2,0.3,0.5,1.0,1.5,2.0,3.0,5.0 to -9999 from time =3 seconds
Hello AdrianT,
it's not really clear to me what you want to do...
I suspect: you have an array containing values and you want to output them with a fixed timing of 3 seconds: you should use a for loop autoindexing trough your array and sending the value to your indicator/output/whatever. Put a "wait for next multiple" into your for loop.
Or do you want to have a minimum time delay of 3 seconds? Again use a for loop, get the time value and use a InRange&Coerce with minimum set to 3 seconds...
Or you should explain more precisely what you need...
it's not really clear to me what you want to do...
I suspect: you have an array containing values and you want to output them with a fixed timing of 3 seconds: you should use a for loop autoindexing trough your array and sending the value to your indicator/output/whatever. Put a "wait for next multiple" into your for loop.
Or do you want to have a minimum time delay of 3 seconds? Again use a for loop, get the time value and use a InRange&Coerce with minimum set to 3 seconds...
Or you should explain more precisely what you need...
Hello TUDS,
do you use different accounts/nicknames ?
Well, that's easy, at least for a sorted array:
Search for your time-value in the array (Threshold 1D array). Fill all elements from that index till the end with your "error condition" (-9999).
For filling the array you can do: calc how many elements have to be written, "initialize array" with -9999 and number of elements, "replace array subset" with initialized array starting from index. This way you don't need a for loop.
do you use different accounts/nicknames ?
Well, that's easy, at least for a sorted array:
Search for your time-value in the array (Threshold 1D array). Fill all elements from that index till the end with your "error condition" (-9999).
For filling the array you can do: calc how many elements have to be written, "initialize array" with -9999 and number of elements, "replace array subset" with initialized array starting from index. This way you don't need a for loop.
Hello adrianT,
first you asked for filling all elements in an array starting from a given index (=element to be searched).
Now you ask to fill the array up to that index:
It's more or less the same: find the index of the given element, make a for loop and replace all elements from start to that index (or index-1, and don't forget to use a shift register). Or as I mentioned above: create an array with "Initialize Array" with the needed number of elements and replace all elements in one step.
You speak of "rows"? Do you have a 2d-array or a 1d-array? (Well it's nearly the same, you just have one index more to keep an eye on...)
first you asked for filling all elements in an array starting from a given index (=element to be searched).
Now you ask to fill the array up to that index:
It's more or less the same: find the index of the given element, make a for loop and replace all elements from start to that index (or index-1, and don't forget to use a shift register). Or as I mentioned above: create an array with "Initialize Array" with the needed number of elements and replace all elements in one step.
You speak of "rows"? Do you have a 2d-array or a 1d-array? (Well it's nearly the same, you just have one index more to keep an eye on...)
