labview 5.1 can't use index array with 2D array

[Shellpetal]

I am using LabVIEW 5.1 and I'm trying to replace the xaxis of a graph with a calibrated x axis. To do this I must replace one dimension of the 2D array which is generated by my camera. The problem is that I can't use the index array function with this data. The input is a 2D array of singles. Is there something I should do to this array first?  I also tried the replace index array vi but that also wouldn't accept my array. What are my options?

Thanks

[tst]

Maybe these wil help?

http://forums.ni.com/ni/board/message?board.id=170&message.id=22518&requireLogin=False

http://forums.ni.com/ni/board/message?board.id=170&message.id=39731&requireLogin=False

[altenbach]

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@Shellpetal wrote:
To do this I must replace one dimension of the 2D array which is generated by my camera. The problem is that I can't use the index array function with this data. The input is a 2D array of singles.

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I don't understand how you want to replace one "dimension" of a 2D array. Are you possibly trying to replace one row or column instead?

I am pretty sure that index array will work with 2D arrays, even in 5.1. It seems you want to replace existing values, so "replace array element" is probably the right function. I would just autoindex the 2D array using a for loop, then you only get a 1D array inside the loop where you can replace desired element. I think I still have an old computer with 5.1 (or even 4.0) at work, so I might be able to look into this next week.

[Shellpetal]

Thanks for the help! My problem was that I wasn't adding a dimension to the replace array element vi. Once I did that it all worked fine.

Cheers