LabVIEW

cancel
Showing results for 
Search instead for 
Did you mean: 

photovoltaic current

Ooops sorry.........heres the vi.

0 Kudos
Message 21 of 86
(1,275 Views)

To be precise, i highlighted the addition equation. see image. i want to add this to the block diagram.

0 Kudos
Message 22 of 86
(1,272 Views)

You'll need to add a subtraction block, that replaces the wire I've starred in green below. (That is right after the ID is calculated) 

 

I'm not sure where you're vaules will come from for I.Rs and Rsh. If they are know constants you can hard code them by using constants. If they are variable inputs I'd recomend making them numeric controls. 

 

The Voltage can be pulled from the red star. After you have all the inputs, you should be able to add and divide them, then throw them into that subtract block. 

 

here.png

 

 

 

 

Applications Engineer
National Instruments
CLD Certified
0 Kudos
Message 23 of 86
(1,220 Views)

Hi Zach, my lecturer told me that I need to change the IL (light source) [see attachment], it is should not be directly connected to the substract. In fact IL is a function of ( light intensity, the material, & efficiency). We should consider it at 1kw/m2. Please consider silicon type of material. How can this be done. Can you write the example for me. Thanks in advance.

0 Kudos
Message 24 of 86
(1,217 Views)

I'm not sure I understand your equation, 1kw/m2 means you're now including an area as well as power instead of current. I think you need figure out what inputs to you want. Lenght, width, resistance, matertial type, etc. After that you'll need to solve for a relation between your inputs and IL. After that you can create your new inputs (as controls or constants) and manipulate them with mathmatic blocks until you have an output of IL. Then route that to the subtract block that our current IL control goes into. 

Applications Engineer
National Instruments
CLD Certified
0 Kudos
Message 25 of 86
(1,201 Views)

@Pooja-S wrote:

Hi Zach, my lecturer told me that I need to change the IL (light source) [see attachment], it is should not be directly connected to the substract. In fact IL is a function of ( light intensity, the material, & efficiency). We should consider it at 1kw/m2. Please consider silicon type of material. How can this be done. Can you write the example for me. Thanks in advance.


Zach has helped you a lot already. Don't you think you should actually try to do some of this homework yourself?

0 Kudos
Message 26 of 86
(1,205 Views)

Hi dear. Yes he has really helped me a lot & i really very thankful to him. But the fact is i am not understanding how to write the code for what i have been told to do. I really hope he will help me out. Thank you for your concern.

0 Kudos
Message 27 of 86
(1,200 Views)

This forum is not a homework-writing service. It seems to me that you are not putting in any effort whatsoever, and are expecting the code to be written for you.

 

 

And please do not call me "dear". Thank you.

0 Kudos
Message 28 of 86
(1,193 Views)

Hello Zach. I have search on internet. My interface should be a bit like this [see image], but as simple than that. The light intensity, irradiance, is at 1kw/m2. But the scale of current IL is different in this graph. I am not sure how this has been done, the code of this program is too complex to understand. If you see my code, any suggestions how IL depends on the irradiance. Do you have the data spefication sheets for silicon solar cell, not module. I mean a small cell which delivers a small power output. We need to consider such type of materials.

Download All
0 Kudos
Message 29 of 86
(1,139 Views)

No I do not have any specification sheets about silicon solar cells. I would be happy to help you with any further LabVIEW issues, but unless you have an idea of what you need to code in LabVIEW I don't think I'll be much help to you.   

Applications Engineer
National Instruments
CLD Certified
0 Kudos
Message 30 of 86
(1,130 Views)