I am using Polynomial Roots VI to solve simple quadratic equation but alwas ge the wrong answer. Let us have simple proplem 2*X^2+2*X+0=0, the roots of thos are -1,0 but the VI gives different roots.
Yes. You are asking the Root Finder to find the roots of a cubic (just because you can't "see" the fourth coefficient in your Constant Array doesn't mean it isn't there ...)
Don't beat yourself up over it. That's why it's always important to have a second set of eyes to look at the problem. 🙂
Bill (Mid-Level minion.) My support system ensures that I don't look totally incompetent. Proud to say that I've progressed beyond knowing just enough to be dangerous. I now know enough to know that I have no clue about anything at all. Humble author of the CLAD Nugget.
