LabVIEW
rearranging bits
Solved!
I have the following array of binary bits
What I want to do is take each of the bits for each of the elements and arrange them as an element for example:
as shown below the 1st 8 bits for each of the elements are arranged on array 2 as an element of 8 bits:
0 ---->00000000
0
0
0
0
0
0
0
I would look at it this way.
Convert the numbers to a boolean array. Do it in a loop to get a 2D array.
Transpose the boolean 2D Array.
Convert each row back to a number withing a loop.
Turns out it also needs to reverse the 1-D boolean arrays before and after the transpose.
I'm sure there are other ways to do this, and some may be more efficient.
But this works.
Of course real programmers really hate to have green bits, because they use 8x more memory. Here's an all blue solution that works just as well. 😄
(I am sure it can be simplified further;))
@altenbach wrote:(I am sure it can be simplified further;))
Plenty of alternatives. Here's another version, same result (many repetitive operations can be precalculated):
Note that this old idea could eliminate the inner FOR loop, so please vote for it. 😄
