Decimal to Hex Value

[geek]

I have a issue where I read in a value:

 buffer[1] = -94 (decimal value) and I am trying to convert it to a hexidecimal number.

My problem is when I use the CVI debugger and look at the hexadecimal value I get 0xA2, but when I try and do a printf

on the same value using %x I get the value FFA2.

I know one value is a 8 bit number and the other is a 16 bit number, but I am trying to figure out how I can extract this value from the buffer and store it into another variable and I am wanting the 8 bit version (0xA2). How can I do this?

I know this is going to be simple but I am drawing a blank right now.

Thanks

[jr_2005]

If you have a 16 bit variable storing a bit pattern of, say, 1111111110100010, the interpretation of this bit pattern depends on the type of the variable. If it is unsigned, the pattern reads as 0xFFA2; if it is signed, it reads as -94. In either event, if you simply copy this value to an 8 bit variable by using a simple assignment statement, only the lower 8 bits will be copied. So how the resulting bit pattern 10100010 is now interpreted again depends on the type of the 8 bit variable. The default CVI char is signed, so it will have the value of -94: if you have an unsigned char it will show as 0xA2 or 162.

JR