What is wrong with this passing a string reference?

[plit string]

I try to send a reference string to my function and hope it will change the content as desired, but it is not! Here how my bad codes are:

int PassStringReference(char *str_ref)
{
     str_ref = "return";

     return 0;
}

void main(void)

{

       int error;

       char *str="string refrence";

       error = PassStringReference(&*str);

       printf("%s", str);

}

The result str = "string reference"???

Can someone show me what I did incorrcetly? By the way, I need to return an integer for other purpose, can not use return string in this case!

Thanks,

[Al_S]

In your syntax

str_ref = "return";

you are creating a string constant.  You should use strcpy instead.

strcpy (str_ref, "return");

Your syntax

PassStringReference(&*str);

is the same as

PassStringReference(str);

[Former NI Employee MS]

Hello

You should try the following:

void main(void)

{

int error;

char str[30]="string reference";  // make sure 30 char is always enough

error = PassStringReference(str);

...

}

Regards,

[plit string]

Your suggestion strcpy is working very well. However, I did try with previous codes with 2 variable strings (for easy showing my problem: I described with constant strings) and it did not work???

Many thanks

[plit string]

I did try but it is the same result, but the other suggest method is working well

Thanks anyway