open ini file

[Axinia]

hello,

i have a little problem ans hope everyone can help me.

I would like to open a *.ini file if I press the button, but the file does not open. can somebody please help me?

---

int CVICALLBACK LoadFile(int panel, int control, int event,   void *callbackData, int eventData1, int eventData2)
{
         switch (event)
        {
              case EVENT_COMMIT:
                   OpenFile("c:\\home\\My Documents\\studium\\File.ini",VAL_READ_WRITE,VAL_OPEN_AS_IS,VAL_ASCII);
                   break;
        }
        return 0;
}

[dummy_decoy · Accepted solution]

i am not sure, what do you expect the OpenFile() function to do ?

OpenFile() opens the file in a programmatic manner: it means that it makes available a value (that you should store in a variable) which allows you to read or write data to/from the file bycalling file manipulation functions like ReadFile() or WriteFile(). it will NOT open the file in your favourite editor !

to open the file in the Windows user Interface meaning of the word, use the function OpenDocumentInDefaultViewer().

[ebalci]

Hi Axinia,

What do you actually want to do when the button is clicked?

Do you want to open a seperate text viewer (like notepad) to see the contents of the file or do you want to read the contents of the file into a string?

The solution depends on your answer.

The code you have provided actually opens a file to be read/written, but you have to assign the return value to a variable in order to access it later.

int fileHandle;
fileHandle = OpenFile (...); 

Hope this helps, 

[Axinia]

thx dummy_decoy

exactly this I have looked 🙂