06-16-2003 11:51 AM
06-17-2003 02:58 PM
11-21-2007 02:39 AM
Dear NI expert,
I have a DAQCard-6024E and a CB-68LP and I want to LVDT +/- 10 volt.
My question are :
1. How many input range of CB-68LP ? Is it depending on DAQCard ?
2. If I want to connect the LVDT to CB-68LP, where is the channel 0,1,2 etc, because on the CB-68LP there are only pin number 1, 35, 2, 36, 3, 37 etc ?
3. Where is the ch+ and ch- on the CB-68LP ? is it need excitation ? if yes where is the pin number ?
Thank's.
Best regards,
Gozali
gmuhamad@gmail.com
11-21-2007
04:39 PM
- last edited on
04-26-2024
05:56 PM
by
Content Cleaner
Hi Gozali,
1. The CB-68LP does not have a input range as it is a connector block. it will be the same as your DAQCard-6024E which is +-10v max.
2. The pinout for the DAQCard-6024E can be found here. When you connect it to your CB-68LP then you'll find the desired function, say AI0 in the pinout chart that I linked to. Then you'll look at the number from the chart and find that number on the CB-68LP, that will be AI0.
3. If you setup a differential task to read your LVDT and are using channel AI0 then the AI0+ will be pin 68 (from the chart on page 13). The AI0- will be pin 34. Differential connections are always paired, simply add 8 to the Differential connector. For example, a differential AI1 connection will use AI1 as the positive input and AI9 as the negative input.
4. The DAQCard-6024E will not provide high current excitation. You could probably use a Analog Output to provide low current (5mA) excitation but for a LVDT that will probably not be sufficient.
Look at our SC-2345 carriers with SCC modules to provide signal conditioning for this application. Your DAQCard-6024E will plug into the SC-2345, your sensors will plug into the SC-2345 and be conditioned.
Please post back if you still have a question regarding how to connect this up.
Best regards,
MatthewW
Applications Engineer
National Instruments