Controlling a relay Using DAQ and Labview

[Seerah]

hi,

i'm a Undergrad student and have started learning LABVIEW just now for my project. I am using NI-DAQ 9263 and i have to connect and control a relay ( am Using LEONE DC6v relay ) using DAQ 9263 . Can u pls tell me how i can go about doing this?? How to give a DC output voltage to the relay?? Do i need to use a current amplifier to amplify current output from DAQ and to give sufficient current to relay?? Or can i directly connect relay to the DAQ ??

Hareesh

[Wilfried_71]

We cannot answer without the spec of your relay : You must check the input voltage and input current of the relay needed to switch the output, and the max current and max voltage available on the NI card output. If the current card output is too low for example, you insert a other component like a relay reed or a optocoupler between the card and your relay ...

Bye

[ryan_d]

Hi Hareesh,

In addition to what Wilfried has asked, I have a few excellent resources for starting out with LabVIEW and DAQ. The first is the LabVIEW Tutorial. The Developer Zone Tutorial: Learn 10 Functions in NI-DAQmx and Handle 80 Percent of Your Data Acquisiti... is a great place to start for the DAQmx driver API. The Data Acquisition Support homepage is another good resource for programming with DAQmx. Finally, there are several shipping examples that may prove useful. They can be found in the Example Finder by going to Help » Find Examples… in LabVIEW.

Post back if you have any questions. Have a great day!

Message Edited by ryan_d on 11-14-2007 09:19 AM

[Seerah]

hi,

Wilfried, i found out the following specificatuions

the input voltage of relay = 6v & input current was 70mA

Current drive of DAQ9263 = +/- 1 mA per cahnnel max

output range = +/- 10V.

how to generate a DC voltage from labview to send to relay via the DAQ??

[Wilfried_71]

OK. Now, it's sure that you cannot connect directly your relay (need of 70 mA) to a DO of your card (current max of 1 mA !!). And this max current of 1 mA is very low. I don't know if you will find a semiconductor in this range of current ... It's just a digital output TTL compatible but not to supply a relay of something like that.