How can I reset shift registers w/o restarting my program?

[Jack 1911]

How can I reset shift register w/o restarting my program? This loop counts the number of failures during a test. Yet, when I run the program again it starts with the last number of failures from the completed test.

[GlennPiper]

I don't have LabView on this PC so I can't see your upload, but my guess is that you simply need to initialize the shift registers. To do this, place a constant outside the loop and wire it to the shift register.

Glenn

[Jack 1911]

Unfortunately think I have done what you stated. If you have time take a look look at it when you get to a PC with Labview. In the application "Failure Count" is wired to a global variable. Would that have any bearing on the ability to reset?

[Dennis_Knutson]

The VI you posted will either display a 0 or 1. It will not increment at all with the false constant wired to the loop termination. Replacing the constant with a control, the fail count will increment and when I restart it, the fail count will start over from 0. If all that you're doing is writing to a global, that shouldn't make any difference. It seems like you tried to make an example similar to your actual application but I think you've missed something. Maybe you could post part of the real program so someone could try to see the difference.

[nanobrain]

Just guessing here, but I think this will do what you intended: