05-19-2013 04:55 AM
Is the USB 6009 PFI0 input the same as the analog circuit input shown in the user manual?
I am using the PFI0 to trigger a voltage measurement and it works great using an HP function generator.
When I try to drive the input low with my circuit it looks like there is a pull up resistor to +5 on the PFI0 input terminal.
Will this PFI0 input accept a 0 to 15 volt comparitor output with being damaged?
Kip
Solved! Go to Solution.
05-19-2013 11:53 AM
After looking at the user manual again, I am guessing that the PFI0 is speced as the other digital input teminnals with a 4.7k resistor to +5. Can you confirm this. Looks like I will have to convert my cmos digital output to TTL.
Can any body confirm this?
05-20-2013 09:25 AM
Here's my solution to drive the PFI0 TTL digital input using a CMOS comparator.
I am using a 2N4401 npn transistor.
Connect the Emitter to the ground terminal.
Connect the Collector to the PFI0 terminal (there is a pull-up resistor internal to the 6009).
Connect the Base to a voltage divider that limits in input current and drops the CMOS voltage to TTL levels.
In my case I am going from 0 to +15 so my voltage divider is 4.7k and 2.2k ohms to drop it down to 0 to +5 volts.
This is an inverting circuit so your trigger sense will change from rising edge to falling edge, or vice versa.
I hope this helps someone out.
Kip