stop dupgg

[when i]

i am used in my project measurement studio and i have two timer one to draw graph and another to make calculate to give the graph timer it's data

(one timer dependent onthe other ) and whn i put build it gives me no error and it success but in the debug it stop automaticly

i dont know why ?

plz tell me

[Eric_B.]

when i,

So you have two timers in your project, and your project builds, but it does not run properly?  What language are you writing in? (C#, C++, VB)  Can you post some code of how you are doing this?

[when i]

i thax about your reply i used vb.net and measurement studio virsion 8.1

and i will tell u simple example take any example from anyproject and in the main timer writ simple code like out ($834,2)

and make debug

u will it run and the stop automaticly

and neally i will send u the code

[Eric_B.]

when i,

I tried implementing what you suggested, but I think I am not understanding completely.  Can you post some code that reproduces this error?

[when i]

Private Sub timer_plot_Tick(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles timer_plot.Tick

 dim s as double

s= out (&h34)

pressure_wave.PlotYAppend(s)

   End Sub

"s" is a double came from parallel port

and i need make update to data after each time

[Eric_B.]

I am not even able to build that code.  What is the out function you are referring to?  My compiler does not know where that is coming from.  Is this a driver function you are using?  What does the "&h34" parameter you are passing to it mean?