03-23-2014 06:23 AM
Hi,
Please, I tried the circuit attached on multisim about transistor function but not works there is current pass throw collector of transistor but the voltage between collector and emitter shows that the like it is open as shown on attachment
03-23-2014 11:04 AM
What is the voltage drop across an ideal inductor with a constant direct current flowing through it? Zero.
To get a voltage at the collector different from V1, you need to have a resistance in the circuit or a time varying current in the inductor. Please review your basic circuit theory.
Lynn
03-24-2014 06:24 AM
thank you for reply, but what it means the current that passes throw collector about 10 ma, if transistor is blocked the current passes throw circuit will be very Small and it is current of base
03-24-2014 01:10 PM
Your circuit has a base current of about 5.4 uA. The collector current is measured as 10 mA, which seems reasonable for the devices and values shown. These values are all constants. Any transients which would occur, for example, when the power supply turns on, have died out. The simuation only shows the steady state condition.
The voltage across the inductor is given by v(t) = L*(di/dt). Because we are looking at the steady state condition, di/dt equals zero by definition. Therefore the voltage across the inductor is also zero. This is what your simuation shows.
I do not understand your comment about the transistor being blocked but that seems to be irrelevant here.
Any real inductor not made of superconducting wire will have non-zero resistance. You could model that by placing a resistor RL1 in series with L1. The value might be ~0.1 ohm. Then the collector voltage would be 5.999V.
Lynn