04-30-2019 04:09 PM
So I know that if you set your sample bit width to 16-bit you get an actual resolution of 14 bits meaning 2 bits are not used. My question is which bits these are in the context of the entire memory space of the sample. In other words, are the 2 unused bits MSB or LSB?
Solved! Go to Solution.
05-01-2019 04:48 PM
Hi JoeSchmoe,
The 2 unused bits are LSB.