11-20-2012 11:35 AM
I wanted to use the Spartan-6 LX45, so I selected the 9146, which is a 4 slots chassis. Later I realized that I needed 8 slots, so I selected the NI 9148. However, I just realized that the NI 9148 has a different FPGA. It has the Spartan-3 2000 instead. Does the 9146 has an 8 slots equivalent? If not, why? It is kind of strange that it only has a 4 slots, and it is a more powerful FPGA.
11-21-2012
12:28 PM
- last edited on
05-13-2024
11:04 AM
by
Content Cleaner
Hi, If you need 8 slots you can use the 9074, it has a Spartan 3 - 2 Million Gate FPGA or you can assemble any controller with the cRIO-9114 (LX50).
The 9146 & 9148 have different FPGAs which makes difficult to calculate and compare their size, however, if you look at the Family Data Sheet for each ( Spartan 3 & 6) you can say that 9148 has an older, yet bigger FPGA and the 9146 a newer, resource efficient but smaller FPGA.
In general, the concern is: "will my code fit in this target?". Good news is that you can simulate the device and compile the code, when done it will tell you if it fits or not. If you get a good result, you can take the code already compiled and put it directly in the real hardware.
I hope this answer your question.
References:
- Resource Utilization Statistics for FPGA VIs
- How to Simulate FPGA Hardware Targets Using the Project Explorer with LabVIEW
- How Do I Download a Bitfile to My Target Without LabVIEW FPGA?