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What is the accuracy of an SCC-RTD01

I need to know what, or how to calculate, the accuracy of an SCC-RTD01 from the specifications and could use some assistance.

 

My total system will use a thin-film platinum RTD (100 Ω at 0°C, temp coefficient of 0.00385 Ω/Ω/°C), connected via 4-wire to the SCC-RTD01 installed in a SCC-68 I/O connector block and digitized by a PXI-6251. 

 

NI's online accuracy calculator conveniently provides the calculated accuracy for the PXI-6251.

 Any help is appreciated- 

 

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Message 1 of 9
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The spec of the SCC-RTD01 tell me a 1.2% gain error 😮  as the biggest point. However with a RTD simulator this could be calibrated and compensated.

 

 

Message Edited by Henrik Volkers on 02-26-2010 09:10 AM
Greetings from Germany
Henrik

LV since v3.1

“ground” is a convenient fantasy

'˙˙˙˙uıɐƃɐ lɐıp puɐ °06 ǝuoɥd ɹnoʎ uɹnʇ ǝsɐǝld 'ʎɹɐuıƃɐɯı sı pǝlɐıp ǝʌɐɥ noʎ ɹǝqɯnu ǝɥʇ'


Message 2 of 9
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Thanks for the info on the RTD simulator.  I was not aware of their existance - maybe our calibation guys have one...

 

Anyway, so I can estimate that the 1.2% gain error will be the majority of the error but I'd like to know (for my own informatoin) how I would include the +/- 250uV (RTI) for the offset error.  The RTI part is confusing me.

 

Also,  your RTD simulator leads me to a new question (I don't have the equiptment yet so I can't check myself).  Can I store this calibration/compensation value provided by the RTD simulator somewhere in MAX or will I have to write code to do the compensation.

 

thanks-

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I hope I am calculating something wrong but my estimation for the accuracy for the overall voltage measurement for the system is about +/- 2mV and a resistance accuracy of about +/- 2 ohm.  This translates to an accuracy of only 5 deg. C.  Can this be true?

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If I remember right you can enter custom coefficients for the Callendar van Dusen equation. So it should be possible, however it will need some preprocessing to get these values.


 

Greetings from Germany
Henrik

LV since v3.1

“ground” is a convenient fantasy

'˙˙˙˙uıɐƃɐ lɐıp puɐ °06 ǝuoɥd ɹnoʎ uɹnʇ ǝsɐǝld 'ʎɹɐuıƃɐɯı sı pǝlɐıp ǝʌɐɥ noʎ ɹǝqɯnu ǝɥʇ'


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So, I am toying with a new idea that will help even if the my accuracy is this low and I don't have use of an RTD simulator.  What if I use a thermister instead.  They have a much greater sensitivity at my temperature range (my measurements will be at room temperature).  What I am thinking is to use the current source of the SCC-RTD01 only and route the voltage directly to the DAQ by passing the gain stage of the SCC-RTD01 (the SCC-RTD01 has a limit of 400mV input range).  If I read the specification correctly the excitation current can withstand up to 24V (without regulation loss).  I will choose thermistor that has 3k ohms at room temperature so my DAQ range will be +/- 5V.  Any thoughts?
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Message 6 of 9
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Powerloos in the thermistor? Selfheating?

 

Greetings from Germany
Henrik

LV since v3.1

“ground” is a convenient fantasy

'˙˙˙˙uıɐƃɐ lɐıp puɐ °06 ǝuoɥd ɹnoʎ uɹnʇ ǝsɐǝld 'ʎɹɐuıƃɐɯı sı pǝlɐıp ǝʌɐɥ noʎ ɹǝqɯnu ǝɥʇ'


Message 7 of 9
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1 mw/°C min. in still air (for example thermistor).  So for 1mA and 3k ohm that is 3mW or 3°C self heating, damn-
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Message 8 of 9
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Even if you don't have a RTD simulator/calibrator  , two 100R  and a good voltage meter (4+ digit) can give you the same answers. Generous people also spend  big Cs in parallel 😉

 

Connect both R in series to the current source and allow 20 min to settle. Measure alternativ with the SCC/DAQ  and the DVM  the 100mV and 200mV 

 

Greetings from Germany
Henrik

LV since v3.1

“ground” is a convenient fantasy

'˙˙˙˙uıɐƃɐ lɐıp puɐ °06 ǝuoɥd ɹnoʎ uɹnʇ ǝsɐǝld 'ʎɹɐuıƃɐɯı sı pǝlɐıp ǝʌɐɥ noʎ ɹǝqɯnu ǝɥʇ'


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