For Loop

[SercoSteveB]

What is the value in Numeric Value Out following execution of the VI?

a) 0

b) 7

c) 14

d) Undefined (The VI does not Stop)

[faymia]

I am going to say that the answer is b) 7 because the loop will only iterate zero times because of the empty array and the value in the shift register just passes through.

[Ajay_MV]

At first I thought it would be a) 0.  But only after testing the code I saw that shift register is there and found shift register brings the data to the other end as well.  Hence the answer is b)7.

[mini09]

Since the empty array is connected to the for loop, the loop will take the miminum no of initialization the array with zero elements is taken by the for loopo and the loop executes zero times.

as the shift register is connected to the loop the value of shift register is taken as the output of numeric value out.

so the numeric value out of the executed program is 7. option B

[JÞB]

"I saw that shift register is there and found shift register brings the data to the other end as well.  Hence the answer is b)7."

To add 1 small point.  Shift registers are required to be "Inplace".  That means they point to the same buffer (the area in memory where the data is located)  We can operate on that data inside the loop, even change the data in the buffer and, with some operations like build array, we may even change the size and location of the buffer (which is why we avoid building arrays in loops) but there is ONE shift register pointing to one buffer represented on both sides of the for loop.  since nothing happened inside the for loop, because it iterated zero times, the data in the buffer could not be changed. b)7

[SercoSteveB]

Answer: B. Nice one faymia, AjayvigneshMV , gnshmrthy & JeffBohrer. Nice combined explanations from everyone.

Yep; a bit of a smoke screen on this one, place some complex (ish) looking code inside the For Loop and then don't execute it. 

[RAMESHB]

Ans is B)7

[ashwinilele]

Ans is7 because of shift register

[skian]

B