Webcast Wednesday Contest # 12

[Webcast_Wednesday_India]

Question 1) The indices of Array 1 and Array 2 are ( 4,5,3,1,4) and (8,3,2,4,1) . How many no. of total iterations are completed?

Question 2) A Boolean array has values [ T,T,T,F,F ]. What will be value of "Array" when value of first Boolean control from array is changed to False?

Question 3) What is the data type of the Indicator that will be present at the Index Array output after the following code has executed? (The input data is of double representation)

Question 4) Which of the following statements is not true regarding the figure below?

1. It is not necessary to wire the count (N) terminal because auto-indexing is enabled.
2. Elements of Input Array enter the loop one at a time.
3. Output Array is the same size as Input Array.
4. If you disable auto-indexing on the right side of the For Loop, the output is still a 1-D Array.
5. All of the above statements are true

Question 5) What is the sustained Loop iteration time for following loop ?

Click here to submit your Answer

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• Post your answers as comments on this thread.
  
• The participant answering all the questions correctly and in the shortest time will be the winner.
  
• In case of a participant submitting multiple comments (answers), the first entry will be considered.
• The deadline for answer submission is next Monday. Entries made after Monday will not be accepted.
• Entries made after the deadline will not be accepted.
• The winner will be announced in the next session of Webcast Wednesday and on this thread, with further information & next steps.
  

[sayantan17]

1. 120

2. [T,T,T,F,F]

3. Value of double representation, i.e. number 6 will be the output

4. option 4

5. 205ms

[nsandeep440]

1: Total no. of Iterations completed are 1 (one)

2: Array Value is same as input Boolean array i.e. [ T,T,T,F,F] in terms of value it is 7

3: Output data is of double representation with 1-D array and output is Array [1,5,0]

4: D

5: 14000 milliseconds

this is to best of my knowledge if any corrections post a comment

thankyou

from Sandeep

[MoatazKamel]

Question 1)

Total iterations completed: 24 iterations

Question 2)

Will instantaneously revert to [T,T,T,F,F]

Question 3)

Numeric indicator of double precision representation

Question 4)

Statements 4 & 5 are not true

Question 5)

205 ms

[mini09]

Hi friends,

Here is my answer,

Question 1: Answer is "0"

Question 2: Answer is "TTTFF"

Question 3: Answer is "DBL"

Question 4: Answer is "4. If you disable auto-indexing on the right side of the For Loop, the output is still a 1-D Array"

Question 5: Answer is "200ms"

all the best friends..

[Paarth]

Q 1: Ans. = 0

Q 2: Ans. = TTTFF

Q 3: Ans. = Double (DBL)

Q 4: Ans. = 4 & 5

Q 5: Ans. = 205 ms

Wram Regards,

Parth Somaiya

[saki]

Q 1 : Total no of iterations completed is 15

Q 2 : TTTFF

Q 3 : numeric indiactor with element 6(DBL representaion)

Q 4 : D - If you disable auto indexing, it will be the last element of the array

Q 5 : it is 200ms

[vignesh-EEE]

1. Number of total iterations=5*4*3*2*1=120.

2. [T,T,T,F,F],Value of array is 7.

3. 1D array is [8,6,3,1,5], Element -6 is the output ad is of double representation.

4. option-4 & 5.If auto indexing is disabled,the value passed out of loop only in last iteration is stored &  not a 1D array.

5. 205 milliseconds.

By,

Vignesh.

[Webcast_Wednesday_India]

Hello all,

The answers posted by you all seems quite interesting.

I see some ambiguity in the last question. There is a fundamental difference between a wait and wait until operation in LabVIEW. It can be found here https://knowledge.ni.com/KnowledgeArticleDetails?id=kA00Z000000P82BSAS&l=en-US. The wait until operation is used to synchronize the code with the system clock whereas the wait operation is used to add a delay between iteration irrespective of the system clock.

I would like to see some explaination to the timing answers. One of the two - 200/205 is correct. Please tell us how you arrived at the solution.

Regards,

Jagriti

[RajivM]

1. Total no of iterations completed is 15

2. TTTFF

3. Output is 1, 5, 0

4. D

5. Runing contineously and Infinity Value of time

Thanks & Regards,

Rajivgandhi Mani

[Webcast_Wednesday_India]

Hello Sandeep

Some feedback on your answers -

1. How did you calculate the iteration count to be 1? It is a 5D array, which is auto-indexed at every for loop. You can read more on autoindexing here https://www.ni.com/docs/en-US/bundle/labview/page/processing-individual-elements-in-an-array-or-a-co...

2. In your third answer, you have not considered the concatenate option in build array. More is given here https://knowledge.ni.com/KnowledgeArticleDetails?id=kA00Z0000019MORSA2&l=en-US

Regards,

Jagriti

[Webcast_Wednesday_India]

Hi Ganesha

Kudos for actively participating in the contests!

Kindly explain how you arrived at the solutions for questions 1 and 5.

Regards,

Jagriti

[mini09]

Hi Team Webcast wednesday,

                                   Thanks for the Kudos....!!!!

1. The indices values are given not the element value of an array so the array is empty array. When you connect an empty array with auto indexing enabled the loop will also take the size of the array as an N. But when N and auto indexing are connected together the for loop will run for the least number of N. Here since the array size is empty the for loop run`s 0 time. so the I iteration is zero. (Only while loop will run once even the function assigned to stop is 0).

2. I was not sure of the answer initially so tryed simulating it, Made the stop terminal to stop when the loop runs once. Used Tick count with the sequence structure on either side of the loop subtracted it got the result as 200ms.