Re : Re: Shift into an array

[Norbert_B]

Just playing around a bit....



please note that this is completly done in LV without changes made in Paint!


Norbert

[Edit] This is all about style guides, isn't it? 🙂


Message Edited by Norbert B on 07-16-2008 07:06 AM

[Ray.R]

Are you referring to the example I posted?  If so, yes, done in Paint. 

I was lazy 😉

[JB]

---

JoeLabView a écrit:

Are you referring to the example I posted?  If so, yes, done in Paint. 

I was lazy 😉

---

Yes.

"Ceci explique cela !"

[smercurio_fc]

Hmmm.. Let's see.. I can turn left, hop across the intersection, go down to the subway, take the subway north, go up the subway stairs, take the trolley to 54th street, get off, take the bus down to 5th, hail a cab, get out, walk three blocks, hop onto the helicopter that's waiting for me, get off at the rooftop, take the elevators down, and then walk out the front door.

-OR-

I can just walk across the street.

This:


vs

this:
 

from: http://forums.ni.com/ni/board/message?board.id=170&message.id=342500

[Wayne.C]

Maybe they were just trying to rack up some more 'frequent wire' miles? 

[Ray.R]

now... How could I miss that one as a R-G code???  LOL!  Good catch smercurio

[GerdW]

Hi,

more classic Rube-Goldberg code in here...

[altenbach]

1. Transpose the Nx2 to a 2xN 2D array
2. Reshape the array to a 1D array of size 2N
3. Split the array at postion N
4. (Here we are actually done, but the shown code does two more splits of the result to ensure that nothing is left at the end :o.) 

Sorry, if you cannot figure out the code, load it in 8.6 and do a quick cleanup with the cleanup button. It does wonders here. 😉

To ensure proper operation, we also need to multiply by 1 and to keep the universe in balance we need to ensure that 50% of the wires flow right-to-left. For artistic values, let's make at least 5 coercion dots. (Cherries on top!) 😄

(See the original thread for better alternatives.)

A possible alternative:

Message Edited by altenbach on 08-19-2008 01:32 PM

[altenbach]

Hmm....

What's the purpose of the outer loop??? Once stop is pressed, the inner loop stops, but since the outer stop button has already been read,

the inner loop will spin once more before the outer loop can stop. Why??

A better solution:

1. Make the boolean "latch action" and wire it in the inner loop in place of the local.
2. Delete the outer loop.
3. Delete the "write local" and diagram constant.

(Original source)

Message Edited by altenbach on 08-27-2008 08:52 AM

[altenbach]

To unflatten a little endian string to a 2D I16 array is a near atomic operation (see 1) ,

...but just for fun, we could use a FOR loop and a formula node instead (see 2).

Both give the same result.

(adapted from this post)

Message Edited by altenbach on 08-28-2008 12:17 PM