How to calculate a new channel equal to the max of each point of 2 channels

[Boulive69]

Hi all,

In DIAdem,

How to calculate a new channel equal to the max of each point of  2 channels (lenght = 1500)

Thank you

[Brad_Turpin]

Hi Boulive69,

If you have DIAdem 10.1 or later you can use the ChnCalculate() expression, otherwise you can use the FormulaCalc() expression.

L1 = CNo("[1]/[1]")

L2 = CNo("[1]/[2]")

Call ChnCalculate("Ch(""Max"") = IIF(Ch(L1) > Ch(L2), Ch(L1), Ch(L2))")

Call FormulaCalc("Ch('Max'):= Ch(L1)*(Ch(L1)>=Ch(L2)) + Ch(L2)*(Ch(L1)<Ch(L2))")

Brad Turpin
DIAdem Product Support Engineer
National Instruments