I think the OP's question rather refers to reverse the logic level of the output. Usually (in non-inverting mode) an activated output refers to a physically high state (min. 2.8V) of the digital output line. I am not familiar with the driver software of this board but with other boards I have seen it is possible to set the digital output(s) to inverting mode. In this case, activating an output refers to a physically low state (max. 0.8V).
Check the output specs of your board to make sure it can supply (or sink, see below) enough current to drive the solenoid.
Since the output voltage in physically high state usually is not very well defined and can be anywhere in the range of 2.8 to 5.0V, usually you connect solenoids in sink mode. I.e., one terminal of the solenoid is connected to +5V and the other one to the digital output. This makes definition of the logic state somewhat more puzzling. You should set the outputs to inverting mode (if possible). If an output is activated, the voltage will drop to close to 0V, thus generating a voltage drop of close to 5V across the solenoid.
In any case, make sure to add a clamping diode in parallel with the solenoid. The cathode must be connected to the terminal with lower voltage, the anode to the terminal with higher voltage.
