gw instek: higher output voltage

[a_babs]

Hey All,

I am currently using a GW Instek PSM-2010 programmable DC power supply and I have been trying to progarmmably increase the voltage output while performing temperature ramps on my sample. At the present time, I am only able to reach a voltage of about 1.2 with a max current of 20 amps. Theoretically I should be able to operate at 8 V when using a max current of 20A. Does anyone know what driver VI will allow me to reach this capability? Or does the problem lay within the temperature ramp programming that was established by my predecesor? When I try to change values in some of the driver VI's that are used in my programming, they seem to reset to a default value. Any insight would be much appreciated. Thanks! - A_babs

[Henrik_Volkers]

Current limit of the power supply?

Even if you set a higher output voltage, if you have a 0.06 Ohm load, the current limiter to 20A will reduce the output voltage.

[crossrulz]

The output current is also the first thing I would check.  If you are putting out the full 20A, then you have an issue.  You really might want to do a continuity check on your device just to make sure something isn't shorted out.

1.2V * 20A = 24 Ohms.

8V * 20A = 160 Ohms.

[Henrik_Volkers]

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@crossrulz wrote:

The output current is also the first thing I would check.  If you are putting out the full 20A, then you have an issue.  You really might want to do a continuity check on your device just to make sure something isn't shorted out.

1.2V * 20A = 24 Ohms.

8V * 20A = 160 Ohms.

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Sorry, isn't it U=R*I ?   😄  😄

[AnalogKid2DigitalMan]

Watt?  🙂

-AK2DM

[crossrulz]

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@Henrik_Volkers wrote:

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@crossrulz wrote:

The output current is also the first thing I would check.  If you are putting out the full 20A, then you have an issue.  You really might want to do a continuity check on your device just to make sure something isn't shorted out.

1.2V * 20A = 24 Ohms.

8V * 20A = 160 Ohms.

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Sorry, isn't it U=R*I ?   😄  😄

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Oops.  It was really early in the morning.  I wasn't totally awake yet.  V = I*R => R = V/I

1.2V/20A = 60mOhms (YIKES)

8V/20A = 400mOhms (I really hope this isn't normal)

[a_babs]

My sample is a tungsten single crystal and has a very high electrical resistance which is part of the problem. I havent had any issues heating my other samples in the past.

[JÞB]

Alpha or beta phase crystal?  the conductance of tungsten should fall between aluminum and nickel if I remember my high school chem teacher right.  

It sounds like the sample is flawed.