A quesiton about case structure

[stephenzhou74]

Hello

I just try to write a simple program.

e.g. I have a for loop (N = 10), if i > 5, I want to output the value into array ([6, 7, 8, 9] is what I want). But in labview I have to wire a value in the "false" case, so my output become [0, 0, 0, 0, 0, 0, 6, 7, 8, 9].

How can I solve this problem?

Many thanks,
Stephen

[Darren]

Hi Stephen,

You need to use a shift register for the array.  In the first half of the iterations, don't add anything to your array.  But once the iteration count passes your threshold, start building the iterations into the array.  I have attached a VI to this e-mail.  Notice also that I've included the logic for switching out cases directly in the case structure with the "..4" and "5.." cases.

You should check out the LabVIEW Help on shift registers...they're a little hard to understand when you first start using LabVIEW, but they are an indispensable feature when dealing with loops.  While you're at it, check out the LabVIEW Help on Case Structures to learn about other neat things like the "..4" and "5.." notation.

-D

[mfitzsimons]

Shift Registers - See Example

[Tushar_Jambhekar]

Try This

[stephenzhou74]

Thanks for everyone's reply.

It is very helpful, you guys are the best, thanks.