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About the Nonlinear System Solver

I think the original equations require that sin(P)=0 and sin(W)=0 and 0<b.

(B/2b)[sin(P)/sin(B)] = 0

(B/2b)[sin(W)/sin(A)] = 0

If so, there would be a finite set of candidate values for P and W (0<=P<=180, 0<=W<=180) implying solutions only exist for specific constant values (A+B).
 
For those solutions, b can be anything (>0)
 
... at least according to the original equations - and a rapidly decaying memory. 
 
what think?
When they give imbeciles handicap-parking, I won't have so far to walk!
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Message 11 of 13
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The equations are not in a website. I made them with the Sine Law. I attached a picture (made in Paint Robot tongue) that describes the system. If you find another way to get mainly "b" and "P", please let me know.
=)

And yes, "b" must be >0.

Message Edited by MiGSPiNe on 10-30-2005 01:01 AM

Message Edited by MiGSPiNe on 10-30-2005 01:02 AM

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Message 12 of 13
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Doh myself, the first two equations are not equaled to 0. They are equaled to 1.
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Message 13 of 13
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