Automatically changing case structure

[Craig1988]

Hello

The vi I have been building has a case structure inside a for loop. I was wanting to have the case structure change every time the loop completes. For example I was wanting to use a string selection input, if the case names are ABCDE and I type in the string input ABCDE could I get the case structure to go A B C D E? Is this possible or any other way I can do this.

[TCPlomp]

Let me see if I understood your question correctly:

You have a case structure with multiple states (A, B, C, D and E) and you have a string that has an order of letters in which you want to execute the cases.

What you could do is use the 'String subset'  function, with the 'i' counter as the starting position and a length of 1.

For 'N' you should take the length of the string.

Ton

[Craig1988]

I'm a university student and quite new to Labview. That is my plan as how it is to work. If it is at all possible could you post a basic vi of this working.

Thanks

Craig McMillan

[TCPlomp]

What kind of code do you have at the moment?

Ton

[Craig1988]

The vi i have built below is what i am wanting to use. The two array constants are what i intend to put in a case state. Then have other cases. As you can see the graph will display other letters that are in the different cases, well that is the idea. So if i have a string input i would like it to output a word on the X-Y graph.

Thanks

Craig McMillan

[Craig1988]

Forgot to post Vi

[altenbach]

First of all, you have way too much code:

There is no reason for the local variable. Just branch the wire to enforce execution order.

There is no reason for the sequence structure once you get rid of the local variable.

The small FOR loop does not do anything useful, right?

There is no reason for the built xy graph express VI monster. Use complex data.

What you could do:

Create a lookup table of small complex arrays, one for each desired letter.

(Since the arrays have different length use a cluster array. You might even append a NaN+NaN to each letter in case you want to ever show more than one at a time, This way you get a gap).

Index into the lookup table to get the desired character.

Here's a very quick draft to give you some ideas (LV 2010). This example toggles between E and F, depending if the iteration is even or odd. Modify as desired.

[Craig1988]

Would it be possible if you would show me how to use a lookup table in this situation or a NaN+NaN? Not sure how to work either.

Thanks

Craig McMillan