Blinking and cluster

[Nick]

Hello!

I am working with LabView 5.1.
And I have problem.
There are indicators in a cluster.
Blinking attribute of some indicators is on.
I want to make unvisible all elements of the cluster.
I set visible attribute of the cluster to off, but blinking indicators are
visible.
How can I make all elements of the cluster unvisible?

With best regards, Nick.

[sincebaugh]

Nick

not sure how many indicators you have, but you can create attribute nodes
for individual indicators and make them not visible, rather than just manipulating
the cluster attribute node.

pat

"Nick" wrote:
>Hello!>>I am working with LabView 5.1.>And I have problem.>There are indicators
in a cluster.>Blinking attribute of some indicators is on.>I want to make
unvisible all elements of the cluster.>I set visible attribute of the cluster
to off, but blinking indicators are>visible.>How can I make all elements
of the cluster unvisible?>>With best regards, Nick.>>>

[Kevin_work]

Nick wrote:

> Hello!
>
> I am working with LabView 5.1.
> And I have problem.
> There are indicators in a cluster.
> Blinking attribute of some indicators is on.
> I want to make unvisible all elements of the cluster.
> I set visible attribute of the cluster to off, but blinking indicators are
> visible.
> How can I make all elements of the cluster unvisible?
>
> With best regards, Nick.

I am afraid that you will have to set the blinking elements to not blink.
That is the only way (I know of) to make them invisible.
Kevin Kent

[Roxanne Constable]

Nick, You need to first set the blinking attribute of the individual elements
in the cluster to false. That should help your problem.
Roxanne

Nick wrote:

> Hello!
>
> I am working with LabView 5.1.
> And I have problem.
> There are indicators in a cluster.
> Blinking attribute of some indicators is on.
> I want to make unvisible all elements of the cluster.
> I set visible attribute of the cluster to off, but blinking indicators are
> visible.
> How can I make all elements of the cluster unvisible?
>
> With best regards, Nick.